(7x-2)^2-(x-4)*(x+4)=(8x+1)*(8x-1)-(4x+3)^2+30

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Solution for (7x-2)^2-(x-4)*(x+4)=(8x+1)*(8x-1)-(4x+3)^2+30 equation: 



(7x-2)^2-(x-4)(x+4)=(8x+1)(8x-1)-(4x+3)^2+30

We move all terms to the left:

(7x-2)^2-(x-4)(x+4)-((8x+1)(8x-1)-(4x+3)^2+30)=0

We use the square of the difference formula

x^2+64x^2+(7x-2)^2+16+1=0

We add all the numbers together, and all the variables

65x^2+(7x-2)^2+17=0

We move all terms containing x to the left, all other terms to the right

65x^2+(7x-2)^2=-17

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